Chapter 15 General Organic Chemistry Part 1 by TEACHING CARE Online coaching and tuition classes
Chapter 15 General Organic Chemistry Part 1 by TEACHING CARE Online coaching and tuition classes
The chemical properties of an element depend on the electronic configuration of the outershell. Carbon has four electrons in its outershell.
According to the ground state electronic configuration of carbon, carbon is divalent. Tetravalency of carbon can
be explained by promoting one
2s – electron to a
2pz
orbital. Some energy must be supplied to the system in order to
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effect this promotion. This promotion requires energy about 96 kcal/mol, but this energy is more than regained by the concurrent farmation of chemical bonds.
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6 C ¾¾®
1s2
2s2
2px 2p¢y 2p¢z
1s2
2s1
2px¢ 2py¢ 2pz¢
Carbon in ground state Carbon in excited state
The four valencies of carbon atom are similar and they are symmetrically arranged around the carbon atom. According to Le Bel and Van’t Hoff the four valencies of carbon do not lie in one plane. They are directed towards the corners of a regular tetrahedron with carbon atom at the centre and the angle between any two valencies is 109o28¢.
The organic compounds are carbon compounds consisting of one or more carbon atoms. Carbon must form only covalent bonds, i.e., it should share its valency electrons with other atoms.
According to the modern concept, a covalent bond is formed between two atoms if there is an overlapping of an atomic orbital of one atom with an atomic orbital of another atom. The overlapping is possible by two ways,
- End to end overlapping : This type of overlapping is possible between The molecular bond formed is termed as sigma (s ) bond.
s – s, s – px
and
px – px atomic
- Sidewise or parallel or lateral overlapping : Such overlapping is possible between
p – p
atomic
orbitals. The molecular bond formed is termed as pi (p ) bond.
- The process of mixing atomic orbitals to form a set of new equivalent orbitals is termed as hybridisation. There are three types of hybridisation encountered in carbon These are,
- sp 3 hybridisation (involved in saturated organic compounds containing only single covalent bonds),
- sp 2 hybridisation (involved in organic compounds having carbon linked by double bonds) and
- sp hybridisation (involved in organic compounds having carbon linked by a triple bonds).
Type of hybridisation | Number of orbitals used | Number of unused
p-orbitals |
Bond | Bond angle | Geometry | % s-character |
sp3 | 1s and 3p | Nil | Four –s | 109.5° | Tetrahedral | 25 or 1/4 |
sp2 | 1s and 2p | One | Three –s | 120° | Trigonal | 33.33 or 1/3 |
One –p | ||||||
sp | 1s and 1p | Two | Two –s | 180° | Linear | 50 or 1/2 |
Two –p |
- Determination of hybridisation at different carbon atoms : It can be done by two methods,
- First method : In this method hybridisation can be know by the number of p –
particular atom.
bonds present on that
Number of p– bond/s | 0 | 1 | 2 |
Type of hybridisation | sp3 | sp2 | sp |
Examples : (i)
O
||
CH3 – CH = CH – C – CH3
- CH 2 = C
= CH2
¯
sp3
¯
sp2
¯
sp2
¯
sp2
¯
sp3
¯
sp 2
¯ ¯
sp sp 2
CH3 – CH = CH – CH 2 – C º N (iv) HC º C – CH = CH 2
¯ ¯ ¯ ¯ ¯ ¯ ¯ ¯ ¯ ¯
sp 3
sp 2
sp 2
sp 3
sp sp
sp sp
sp 2 sp 2
Note : ® In diamond carbon is sp3 hybridised and in graphite carbon is
sp 2 hybridised.
- This method can not be used for those atoms of the molecule which have positive charge, negative charge or odd
(ii) Second method : (Electron pair method)
ep = bp + lp; where ep = electron pair present in hybrid orbitals , bp = bond pair present in hybrid orbitals Number of bp = Number of atoms attached to the central atom of the species
Number of lp’s can be determined as follows,
- If carbon has p – bond/s or positive charge or odd electron, than lp on carbon will be
- If carbon has negative charge, then lp will be equal to
Number of electron pairs (ep) tells us the type of hybridisation as follows,
ep | 2 | 3 | 4 | 5 | 6 |
Type of hybridisation | sp | sp2 | sp 3 | sp 3 d | sp 3d 2 |
Example :
Å Q · Q Q
(i) CH 2 = CH
¯
bp = 2
lp = 0
ep = 2, sp
(ii)
CH 2 = CH
¯
bp = 2
lp = 1
ep = 3, sp 2
(iii)
CH 2 = C – CH3
|
CH3
bp = 3
lp = 0
ep = 3, sp 2
(iv)
CH º C
¯
bp=1
lp = 1
ep = 2, sp
(v)
CH3 – CH– CH3
¯
bp=3
lp = 1
ep = 4, sp 3
(3) Applications of hybridisation
- Size of the hybrid orbitals : Since s – orbitals are closer to nucleus than p – orbitals, it is reasonable to expect that greater the s character of an orbital the smaller it is. Thus the decreasing order of the size of the three hybrid orbitals is opposite to that of the decreasing order of s orbital character in the three hybrid
sp3 > sp2 > sp
- Electronegativity of different orbitals
- Electronegativity of s-orbital is
- Electronegativity of hybrid orbital µ % s-character in hybrid orbitals
Orbital
sp sp 2
sp 3
¾¾¾%¾s¾- c¾ha¾ra¾cte¾r
¾¾¾¾5¾0 ¾¾¾¾33¾.33¾¾¾¾¾25¾¾¾¾¾®
s-character in decreasing order and electronegativity in decreasing order
Thus sp-hybrid carbon is always electronegative in character and sp 3 – hybrid carbon is electropositive in
character. sp 2 -hybrid carbon can behave as electropositive (in carbocation) as well as electronegative (in
carbanion) in character.
Å Å
CH3 – CH 2
sp 2
CH2 = CH
sp
Electropositive carbon Electronegative carbon having positive charge
- Electronegativity of different hybrid and unhybrid orbitals in decreasing order is as follows
|
> > 2 > 3 >
¾¾¾¾¾¾¾¾¾¾¾¾¾¾¾¾¾¾¾¾¾¾¾¾¾¾¾¾¾¾¾¾®
% s – character in decreasing order and electronegativity in decreasing order.
- Bond length variation in hydrocarbons
% s orbital character µ 1 µ 1
C – C bond length C – H bond length
Bond type (C – H) | Bond length | Bond type (C – C) | Bond length |
sp 3 – s (alkanes) | 1.112Å | sp3 – sp3 (alkanes) | 1.54 Å |
sp 2 – s (alkenes) | 1.103Å | sp 2 – sp 2 (alkenes) | 1.34Å |
sp – s (alkynes) | 1.08Å | sp – sp (alkynes) | 1.20Å |
Note : ® C–C bond length in benzene lies between single and double bond due to resonance. (1.40Å).
- Bond strength in hydrocarbons : The shorter the bond, the greater the compression between atomic nuclei and hence greater the strength of that bond is. Thus the bond formed by sp hybridised carbon is strongest
(i.e., it has maximum bond energy) while that formed by sp 3 hybridised carbon is the weakest (i.e., it has minimum
bond energy). This is evident by the bond energies of the various types of C – H and C – C bonds.
Bond type (C – H) | Bond energy
(kcal/mole) |
Bond type (C – C) | Bond energy
(kcal/mole) |
sp 3 – s (in alkanes) | 104 | sp3 – sp3 (in alkanes) | 80 – 90 |
sp 2 – s (in alkenes) | 106 | sp 2 – sp 2 (in alkenes) | 122 – 164 |
sp – s (in alkynes) | 121 | sp – sp (in alkynes) | 123 – 199 |
- Acidity of hydrocarbons
- Hydrogen present on electronegative carbon is acidic in character.
- Acidity of hydrogen is directly proportional to the electronegativity of atom on which hydrogen is present. Thus
¾¾H –¾O–H¾¾¾¾NH¾3 ¾¾¾CH¾ºC¾H ®
Electronegativity of atom in decreasing order Acidity of compounds in deceasing order
- Acidity of hydrocarbon µ % s-character
CH º CH
CH 2 = CH 2
CH3 – CH3
% s-character 50 33.33 25
pKa 25 44 50
s– character in decreasing order and acidity in decreasing order
Note : ® Acidity µ Ka and Acidity µ 1 (pKa = – log Ka)
pKa
- Order of acidic nature of alkynes is, HC º CH > HC º C – CH3
- The relative acidic character follows the order;
H2O > ROH > HC º CH > NH3 > CH2 º CH2 > CH3 – CH3
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Obviously, the basic character of their conjugate bases follows the reverse order, i.e.,
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CH3CH > CH2
= CH > NH > HC º C > RO > HO
- Due to differences in electronegativity polarity developes between two adjacent atoms in the molecule (e., in a bond). The degree of polarity of a bond is called dipole moment. Dipole moment is represented by m and its unit is Debye (D).
Where, e =
length in cm.
m = e ´ l
magnitued of separated charge in e.s.u.,
l = internuclear distance between two atoms i.e., bond
The dipole moment is denoted by arrow head pointing towards the positive to the negative end (↦).
- Dipole moment of the compound does not depend only on the polarity of the bond but also depends on the shape of the Dipole moment of symmetrical compound is always zero, ( m = 0 ). Symmetrical compounds are those compounds which fulfil following two conditions,
- Central atom is bonded with the same atoms or Examples :
- Central atom should have no lone pair of
. . . .
H 2 , BF3 , CS2 , CH 2 = CH 2 , CH º CH
Symmetrical molecules
Examples :
CCl4 , CH 4 , BH 3 , CO2 H 2 O, H 2 S
Symmetrical molecules Unsymmetrical molecules
Note : ® Compounds which have regular tetrahedral structure has no dipole moment.
- m µ electronegativity of central atom or surrounding atoms present on the central atom of the
¾¾CH¾F3¾¾¾¾CH¾C¾l3 ¾¾¾C¾H¾Br3¾¾¾¾CH¾I¾3 ®
Electronegativity in decreasing order
m is also in decreasing order
¾¾N¾H¾3 ¾¾¾P H¾3 ¾¾¾¾¾As¾H¾3 ¾¾¾Sb¾H¾3 ¾®
Electronegativity of central atom is in decreasing order m is also in decreasing order
Note : ® Decreasing order of dipole moment in CH3 Cl, CH 2 Cl2 , CHCl3
CH3Cl > CH2Cl2 > CHCl3 > CCl4
m = 1.86 D 1.62 D 1.03 0
and CCl 4 is
- Alkynes has larger dipole moment because the electronegativity of
sp2 – C .
sp – C
is more than that of
- m cis > m trans in geometrical
- Dipole moment of the trans derivative of the compound (a)(b)C = C(a)(b) will only be zero if both a and
b will be in the form of atoms.
H
Example :
X
X
C = C
H
m =0
H H
C = C
X X
m ¹0
( X = Cr, Br, I
or F )
If both will not be atoms then m trans may or may not be zero.
If group have non-linear moments, then the dipole moment of the trans isomer will not be zero. If group have linear moments, then the dipole moment of the trans isomer will be zero.
Example :
H 3 C
C = C
CH3
H
C = C
CH3
H H
m =0.33D
H3 C
H
m =0 D
(6) Dipole moment of disubstituted benzene
- When both groups X and Y are electron donating or both groups are electron with drawing
X X
Y or Y
Then, m =
Where, m1 = dipole moment of bond C – X , m 2 = dipole moment of bond C – Y , q = angle between X and Y.
If value of q will be more, then cosq will be less. Hence, dipole moment will be as,
¾¾o -¾de¾riva¾tiv¾e ¾>¾m¾-de¾riv¾ati¾ve¾>¾p¾-d¾er¾iva¾tiv¾e ®
m in decreasing order
- When one group is electron with drawing and the other group is electron donating then,
m =
Hence, dipole moment is as follows,
¾¾o -¾de¾riva¾tiv¾e ¾>¾m¾-d¾er¾iva¾tiv¾e ¾> ¾p-¾de¾riv¾ativ¾¾e ®
m in decreasing order
On account of the presence of bulkier groups at the reaction centre, they cause mechanical interference and with the result that the attacking reagent finds it difficult to reach the reaction site and thus slows down the reaction. This phenomenon is called steric hinderance or steric effect.
- Tertiary alkyl halides having bulky groups form tertiary carbocation readily when hydrolysed because of
the presence of the three bulky groups on the carbon having halogen.
CH Steric strain around this carbon
3 (More strained species)
|
Steric strain is released (less strained species)
Å
H3C – C – Cl
|
CH
¾¾®
H3 C – C – CH3
3 CH
3
- Primary alkyl halide having quaternary b -carbon does not form transition state because of the steric strain around a -carbon by the b -carbon. To release the strain it converts into
CH3
|
CH3 – C
|
CH
3
Bulky group
CH 2 – Cl
Strained carbon due to bulky group present around this carbon.
- Steric strain inhibits the This phenomenon is known as steric inhibitions of resonance.
In an ionic compound, the structural units are ions. These ions are held together by very powerful electrostatic forces are known as inter ionic forces. On the other hand, in non-ionic (covalent) compounds, the structural units are molecules. These molecules are held together by very weak forces are known as intermolecular forces or secondary forces. Secondary forces are of the following types,
(1) Dipole – dipole forces. (2) Van der Waal’s forces. (3) Hydrogen bond.
- Dipole – Dipole Forces : These forces exist between polar molecules which have permanent dipoles. The interactions of the permanent dipole in different molecules are called dipole-dipole forces (DF). Magnitude of DF depends on the dipole moment (m) of the bond of the compound and intermolecular distance (d),
DF µ m
µ 1 (i.e. these forces are effective only over short distance)
d 4
CH3 – Cl, CH3 – Br, CH3 – I
Example
¾¾¾¾¾¾¾¾¾¾¾¾¾¾¾¾¾¾¾¾¾¾¾¾¾¾¾¾¾¾¾¾®
d in increasing order, m in decreasing order and DF also in decreasing order
- Vander Waal’s forces : These forces exist between non-polar molecules. The intermolecular electrostatic attractions between nuclei of one molecule and electrons of the other molecule are called Vander Waal’s forces (VF). Magnitude of VF depends on the number of electrons (e – ) and protons (p) in the molecule as well as on the intermolecular distance (d),
VF µ number of e – and p; µ 1 / d 7 ; µ MW; µ Surface area of the molecule and
µ Symmetry of the molecule (symmetry of molecule decreases intermolecular distance (d)).
- Hydrogen bonding : An electrostatic attractive force between the covalently bonded hydrogen atom of
one molecule and an electronegative atom (such as
bonding.
F, O, N ) of the other molecule is known as hydrogen
Examples of H-bonding in between the two molecules of same or different compounds are
H – F — H– F
Hydrogen fluoride (associated)
H – O — H – O
| |
H H
Water (associated)
H H
| |
H – N — H – N
| |
H H
Ammonia (associated)
R R
| |
O – H — O – H
Alcohol (associated)
R H
| |
O – H — O – H
Alcohol and Water
H O – H
| |
H – N — H
|
H
Ammonia and water
Nature and Importance of Hydrogen bonding
- Hydrogen bond is merely an electrostatic force rather than a chemical
- Hydrogen bond never involves more than two
- Bond energy of hydrogen bond is in the range of 3 to 10 kcal/mol or 10 to 40 kJ/mol, e., about 1/10th the energy of a covalent bond.
- With the increase of electronegativity of the atom to which hydrogen is covalently linked, the strength of the hydrogen bond
- All the three atoms in X – H– – – X lie in a straight
- The bond length of hydrogen bond is of the order of 250 to 275 pm. The relative order of these intermolecular forces is,
Hydrogen bonding > dipole-dipole forces > Vander waal’s forces.
When a chemical reaction takes place between two or more chemical species, new products are formed. This change is represented by a chemical equation. In a chemical equation, reactants are written on the left hand side while the products are written on the right hand side. The two are separated by an arrow (®). The reactants normally consists of two species,
- Substrate : The species, which is attacked by some other chemical species, is called a
- Reagent : The species, which attacks the substrate in order to get the major product, is called a reagent. Thus, Substrate + Reagent ®
Normally, a substance and a chemical reagent form a highly energetic species, called activated complex, before it changes into the product. In certain cases, a relatively energetically more stable species than the activated complex may also be formed. It is called reaction intermediate. Thus, a chemical reaction, in general, may follow either of the following two paths,
Path I : Substrate + Reagent ® Activated complex ® Products
Path II : Substrate + Reagent ® Activated complex ® Intermediate ® Products.
The detailed step by step description of a chemical reaction is called mechanism of a reaction which is only a hypothesis. If the reaction mechanism involves the breaking and making of bonds simultaneously without the formation of any intermediate, it is called concerted mechanism. On the other hand, if the reaction mechanism involve the formation of intermediates before the formation of products, it is called non-concerted mechanism.
Enthalpy curves for concerted and Non-concerted mechanisms
To understand clearly the mechanism of various organic reactions, it is essential to have knowledge about the following concepts;
- Electronic displacements in covalent bonds,
- Cleavage (fission or breaking) of covalent bonds,
- Nature of attacking
It is observed that most of the attacking reagents always possess either a positive or a negative charge, therefore for a reaction to take place on the covalent bond the latter must possess oppositely charged centres. This is made possible by displacement (partial or complete) of the bonding electrons. The electronic displacement in turn may be due to certain effects, some of which are permanent and others are temporary. The former effects are permanently operating in the molecule and are known as polarisation effects, while the latter are brought into play by the attacking reagent and as soon as the attacking reagent is removed, the electronic displacement disappears; such effects are known as the polarisability effects.
Inductive effect or Transmission effect
- When an electron with drawing (X) or electron-releasing (Y) group is attached to a carbon chain, polarity is induced on the carbon atom and on the substituent attached to it. This permanent polarity is due to electron displacement due to difference in This is called inductive effect or simply as I – effect.
C – C – C – C Non polar
Cdddd +
Cddd +
Cdd +
Cd +
X d –
Cdddd –
Cddd –
Cdd –
Cd –
Y d +
(2) Important features of Inductive effect
- It is a permanent effect in the molecule or
- It operates through s
- It is generally observed in saturated
- The shared pair of electrons although permanently shifted towards more electronegative atom, yet remains in the same valence
- As a result of electron shifting, the more electronegative end acquires partial negative charge and the other acquires partial positive
- The inductive effect is not confined to the polarization of one bond but is transmitted along a chain of carbon atoms through s However, the effect is insignificant beyond second carbon in the chain.
- Inductive effect brings changes in physical properties such as dipole moment, solubility, It affects the rates of the reaction.
- Carbon-hydrogen bond is taken as a standard of inductive effect. Zero effect is assumed for this bond. Atoms or groups which have a greater electron withdrawing capacity than hydrogen are said to have–I effect whereas atoms or groups which have a greater electron releasing power are said to have +I
Å
N H3 > NO2 > CN > SO3 H > CHO > CO > COOH > COCl > COOR > CONH2 > F > Cl > Br > I > OH > OR > NH2 > C6 H5 > H
–I power of groups in decreasing order with respect to the reference H
ter. alkyl > sec. alkyl > pri. alkyl > CH3 > H
+ I power in decreasing order with respect to the reference H
+ I power µ number of carbon’s in same type of alkyl groups
CH3 – CH2 – CH2 – CH2 – > CH3 – CH2 – CH2 – > CH3 – CH2 –
+ I power in decreasing order in same type of alkyl groups
(3) Application of Inductive effect
- Magnitude of positive or negative charge : Magnitude of +ve charge on cations and magnitude of
–ve charge on anions can be compared by + I or – I groups present in it.
- Reactivity of alkyl halide : + I effect of methyl group enhances – I effect of the halogen atom by
repelling the electron towards tertiary carbon atom.
H3 C
CH3 C CH3
X > H3 C
CH3 CH
X > CH3
CH 2
X > CH3 X
Tertiary > Secondary > Primary > Methyl
- Dipole moment : As the inductive effect increases, the dipole moment
CH3 I
CH3 Br
CH3 Cl
1.64 D 1.79 D 1.83 D
Inductive effect increases
- Relative strength of the acids (Acidic nature of – COOH )
- An acid may be defined as a species that has the tendency to loose Furthermore, the strength of an acid depends on the tendency to release proton when the acid is dissolved in water.
O
||
R – C– OH ⇌
O
||
R – C– O + H Å
- The relative strength of acids are measured in their ionisation constants ( Kaor pKa values).
|
HA
Acid
H Å + A ;
K = [H Å ][A ] ;
a [HA]
pKa
= -log Ka
Greater the value of
Ka or lower the value of
pKa
stronger will be the acid.
- Any group or atom showing +I effect decreases the acid strength as it increases the negative charge on the carboxylate ion which holds the hydrogen Alkyl groups have + I effect.
Thus, acidic nature is,
HCOOH > CH3 COOH > C2 H5 COOH > C3 H7 COOH > C4 H9 COOH
(+ Inductive effect increases, so acid strength decreases)
Formic acid, having no alkyl group, is the most acidic among these acids.
- The group or atom having – I effect increases the strength as it decreases the negative charge on the carboxylate Greater is the number of such atoms or groups (having – I effect), greater is the acid strength.
Thus, acidic nature is, CCl3 COOH > CHCl2 COOH > CH 2 ClCOOH > CH3 COOH
Trichloro acetic acid
Dichloro acetic acid
Monochloro acetic acid
Acetic acid
(– Inductive effect increases, so acid strength increases)
- Strength of aliphatic carboxylic acids and benzoic acid
R
+I group
COOH
C6 H5
|
I group
COOH
Hence benzoic acid is stronger acid then aliphatic carboxylic acids but exception is formic acid. Thus,
HCOOH
C6 H5 COOH
RCOOH
Acid strength in decreasing order
Note : ® Decreasing order of acids :
NO2CH2COOH > FCH2COOH > ClCH2COOH > BrCH2COOH .
F3C – COOH > Cl3C – COOH > Br3C – COOH > I3C – COOH .
- Acidity of alcohols : Acidity of alcohol depends on the stability of alkoxide ion (i.e., conjugate base of alcohol) which is obtained by the dissociation of
|
Å
R – O – H
R – O+ H
Alkoxide ion
Acid strength of alcohol µ stability of alkoxide ion
The decreasing order of acid strength of acid strength in alcohols is also due to +I effect of alkyl groups.
CH3OH > CH3CH2OH > (CH3 )2 CHOH > (CH3 )3 COH
Methyl alcohol
Ethyl Alcohol
Iso– propyl alcohol
Tert –butyl alcohol
As compared to water, phenol is more acidic (–I effect) but methyl alcohol is less acidic (+I effect).
- H – OH > CH3 OH
Water
Methyl alcohol
- Relative strength of the bases (Basic nature of – NH2 )
- A base may be defined as a species which is capable of accepting a Base strength is defined as the tendency to donate an electron pair for sharing.
- The relative strength of bases are measured in their ionisation constants ( Kbor pKb values).
|
BOH BÅ + OH ;
Base
K = [BÅ ][OH ] ;
b [BOH]
pKb
= -log Kb
Greater the value of
Kb or lower the value of
pKb
stronger will be the base.
- The difference in base strength in various amines can be explained on the basis of inductive The +I
effect increases the electron density while –I effect decreases. The amines are stronger bases than
NH3
as the alkyl
groups increase electron density on nitrogen due to + I effect while
ClNH2
is less basic due to –I effect. “So more is
the tendency to donate electron pair for coordination with proton, the more is basic nature, i.e., more is the negative charge on nitrogen atom (due to +I effect of alkyl group), the more is basic nature”.
Thus, the basic nature decreases in the order;(C2 H5 )2 NH > CH3CH2 NH2 > CH3 NH2 >
NH3
- ClNH2
The order of basicity is as given below;
Diethyl amine
Ethyl amine
Methyl amine
Ammonia
Chloro amine
Alkyl groups (R–) Relative base strength
CH3
C2 H5
(CH3 )2 CH
(CH3 )3 C
R2 NH > RNH2 > R3 N > NH3 R2 NH > RNH2 > NH3 > R3 N RNH2 > NH3 > R2 NH > R3 N NH3 > RNH2 > R2 NH > R3 N
Note : ® The relative basic character of amines is not in total accordance with inductive effect
(t > s > p)
but it is in the following order: Secondary > Primary > Tertiary. The reason is believed to be steric factor.
- In gas phase or in non aqueous solvents such as chlorobenzene etc, the solvation effect, i.e., the stabilization of the conjugate acid due to H -bonding are absent and hence in these media the basicity of amines depends only on the +I effect of the alkyle group thus the basicity of amines
follows the order : 3o > 2o > 1o > NH3 .
- As compared to ammonia, methylamine is more basic (+I effect) but aniline is less basic and diphenylamine is still more weaker (– I effect).
CH3 NH2 > NH3 > C6 H5 NH2 > (C6 H5 )2 NH
- Basicity of alcohols : The decreasing order of base strength in alcohols is due to +I effect of alkyl
(CH3 )3 COH > (CH3 )2 CHOH > CH3CH2OH > CH3OH
(3o )
(2o )
(1o )
methyl / alcohol
In Lucas test of making distinction between three types (1o,2o
éR – OH+ HCl(conc.) ¾¾anh¾yd. Z¾nC¾l2 ® R – Cl + H Où
and 3o ) of monohydric alcohols,
ëê (Base)
( Acid)
(White ppt.)
2 úû
The basic character of alcohols is in the order, benzyl
> 3o > 2o > 1o
and hence, the strongest base (3o )
will
be reacting fastest with conc. HCl in presence of anhydrous immediately.
ZnCl2
(Lucas reagent) and gives white turbidity
- Stability of carbonium ion :+I effect tends to decrease the (+ve) charge and –I effect tends to increases the +ve charge on
|
|
(CH3 )3 CÅ > (CH3 )2 CH Å > CH3CH Å > CH Å
- Stability of carbanion : Stability of carbanion increases with increasing – I
CH > CH CH > (CH ) CH > (CH ) C
3 3 2 3 2 3 3
Resonance effect or mesomeric effect
- The effect in which p electrons are transferred from a multiple bond to an atom, or from a multiple bond to a single covalent bond or lone pair (s) of electrons from an atom to the adjcent single covalent bond is called mesomeric effect or simply as M-effect. In case the compound in question is having conjugated system of double bonds, the mesomeric effect is transmitted through whole of the conjugated system and thus the effect may better be known as conjugative effect.
(2) Important features of mesomeric effect
- It is a permanent effect present in the molecule in the ground
- It is operative in unsaturated compounds especially having conjugated
- It involves electrons of p -bonds or lone pair of This effect operates through conjugative mechanism.
- In this effect the electron pair is completely transferred and thus full positive and negative charges are
- It affects the physical properties such as dipole moment, solubility Rate of reaction fo the substance is also affected.
- Groups which have the capacity to increase the electron density of the rest of the molecule are said to
have + M effect. Such groups possess lone pairs of electrons. Groups which decrease the electron density of the
rest of the molecule by withdrawing electron pairs are said to have – M effect, e.g.,
- The groups which donate electrons to the double bond or to a conjugated system are said to have + M
effect or + R effect.
. . Å
CH2 = CH – Cl : ¬¾® C H2 – CH = Cl : (+R effect)
. . . .
Vinyl chloride
In vinyl chloride C – Cl bond has double bond character due to resonance.
. . . .
- M effect groups : – Cl, – Br, – I, – N H2 , – NR2 ,-OH,-OR,-SH,-OCH3 ,- S R
. .
- The groups which withdraw electrons form the double bond or from a conjugated system towards itself
due to resonance are said to have – M
Å
effect or – R
effect.
CH2 = CH – C
Vinyl cyanide
: ¬¾® C H2 – CH = C = N :
. .
O
||
( – R
effect)
- M effect groups : – NO2,-C º N, – C -,-CHO,-COOH,-SO3 H
- The inductive and mesomeric effects, when present together, may act in the same direction or oppose each other. The mesomeric effect is more powerful than the former. For example, in vinyl chloride due to – I effect the chlorine atom should develop a negative charge but on account of mesomeric effect it has positive charge.
. . Å ..
: Cl ¬ CH = CH2 ¬¾® : Cl = CH – CH2
. . . .
- Application of mesomeric effect : It explains,
- Low reactivity of aryl and vinyl halides,
- The acidic nature of carboxylic acids,
- Basic character comparison of ethylamine and aniline,
- The stability of some free radicals, carbocations and
- Difference between Resonance and Mesomerism : Although both resonance and mesomerism represent the same phenomenon, they differ in the following respect : Resonance involves all types of electron displacements while mesomerism is noticeable only in those cases where a multiple bond is in conjugation with a multiple bond or electron
.. Å
Example : (i)
H2C = CH – CH = CH2 ¬¾® H2 C– CH = CH – C H2
. . . .
|
: O :O:
|| || Å
(ii) R – C – O– H ¬¾® R – C = O– H
. . . .
Both (i) and (ii) are the examples of mesomerism and resonance effect. Let us consider the following example
. . Å
H Cl : ¬¾® H Cl . Such an electron displacement is the example of resonance only (not the mesomerism).
. .
- When a
H – C
Hyperconjugative effect
bond is attached to an unsaturated system such as double bond or a benzene ring, the
sigma (s) electrons of the
H – C
bond interact or enter into conjugation with the unsaturated system. The
interactions between the electrons of p systems (multiple bonds) and the adjacent s bonds (single
H – C
bonds)
of the substituent groups in organic compounds is called hyperconjugation. The concept of hyperconjugation was developed by Baker and Nathan and is also known as Baker and Nathan effect.
In fact hyperconjugation effect is similar to resonance effect. Since there is no bond between the a -carbon atom and one of the hydrogen atoms, the hyperconjugation is also called no-bond resonance.
- Orbital concept of hyperconjugation : The orbital concept of hyperconjugation may be explained with the help of In this,
the electron pair of C – H bond (s -bond) is involved in conjugation with
the p -electron pair of the double bond. Therefore, hyperconjugation
involves delocalisation of s -electrons of
H – C
bond through
overlapping of p -orbitals of double bond as shown in figure.
(3) Structural requirement for hyperconjugation
- Compound should have at least one
sp 2 -hybrid carbon of either alkene alkyl carbocation or alkyl free
- a -carbon with respect to sp 2 hybrid carbon should have at least one
If both these conditions are fulfilled then hyperconjugation will take place in the molecule.
- Hyperconjugation is of three types
- s (C – H), p conjugation : This type of conjugation occurs in
CH3
|
C H3 – CH = CH 2
a
CH3 – CH – CH = CH 2
|
CH
3
|
CH3 –C –
a|
CH3
CH = CH2
No. hyperconjugation
- s (C – H), positive charge conjugation : This type of conjugation occurs in alkyl
Å a Å a Å a
|
CH3 – CH2
CH3 – CH – CH3
CH3
- C – C H3
|
CH3
a
- s (C – H), odd electron conjugation : This type of conjugation occurs in alkyl free
. a . a
C H3 – C H2 C H3 – C – C H3
a sp2
|
CH3
a
- Resonating structures due to hyperconjugation may be written involving “no bond” between the alpha carbon and hydrogen
|
|
Å
H Å | |
H – C – CH = CH 2 ¬¾® H – C = CH – C H 2 ¬¾® H C = CH – C H 2 ¬¾® H – C = CH – C H 2
| | |
|
H H H H
- Number of resonating structures due to the hyperconjugation = Number of a -hydrogens +
Structure | Number of | a-hydrogens | Number of resonating structures |
CH3 – CH = CH2
CH3 – CH 2 – CH = CH 2 CH3 – CH = CH – CH3 Å CH3 – C H 2 Å CH3 – C– CH3 Å CH3 – C – CH3 | CH3 |
3 | 4 | |
2 | 3 | ||
6 | 7 | ||
3 | 4 | ||
6 | 7 | ||
9 | 10 |
(4) Applications of hyperconjugation
- Stability of alkenes : Hyperconjugation explains the stability of certain alkenes over other Stability of alkenes µ Number of alpha hydrogens µ Number of resonating structures
CH3 – CH = CH2
CH3 – CH2 – CH = CH2
Stability in decreasing order
CH3 – CH – CH = CH2
|
CH3
CH3
C = C
CH3
CH3
CH3
CH3
C = CH – CH3
CH3
CH3
C = CH2
Number of alpha hydrogens in decreasing order stability of alkenes in decreasing order
- Carbon-carbon double bond length in alkenes : As we know that the more is the number of resonating structures, the more will be single bond character in carbon-carbon double
Thus, bond length between carbon double bond µ number of resonating structures. Examples,
Structure | Number of a-hydrogens | Number of resonating structures | Carbon-carbon double bond length in Å |
CH 2 = CH 2
CH3 – CH = CH 2 CH3 – CH 2 – CH = CH 2 CH3 – CH – CH = CH2 | CH 3
CH 3 | CH3 – C – C H = CH2 | CH 3 |
Zero | Zero | 1.34 Å |
3 | 4 | 1.39 Å | |
2 | 3 | 1.37 Å | |
1 | 2 | 1.35 Å | |
Zero |
Zero |
1.34 Å |
(ii) Stability of alkyl carbocations : Stability of alkyl carbocations µ number of resonating structures µ
number of resonating structures µ number of alpha hydrogens.
Å
C H3
Å
CH3 – C H2
Å
CH3 – C H – CH3
Å
CH3 – C – CH3
|
CH3
Number of a-hydrogens in increasing order Stability in increasing order
- Stability of alkyl free radicals : Stability of alkyl free radicals can be explained by hyperconjugation. Stability depends on the number of resonating
Structure
.
C H3
.
CH3 – C H2
.
CH3 – C H – CH3
.
CH3 – C – CH3
|
CH3
No. of resonating structures 0 4 7 10
Number of resonating structures in increasing order Stability is in increasing order
- Electron releasing (or donating) power of R in alkyl benzene :
CH3 – (or alkyl group) is + R
group, ortho-para directing group and activating group for electrophilic aromatic substitution reaction because of the hyperconjugation.
H
|
H – C – H
|
H
|
H – C H Å
||
H
|
H – C H Å
||
H
|
H – C H Å
||
Θ
Θ
The electron donating power of alkyl group will depends on the number of resonating structures, this depends on the number of hydrogens present on a-carbon. The electron releasing power of some groups are as follows,
CH3
CH3
|
CH3 – > CH3 – CH2 –
Increasing inductive effect
>
CH3
CH – >
CH3 – C –
|
CH3
Electron donating power in decreasing order due to the hyperconjugation.
- Heat of hydrogenation : It is the heat evolved/mol in the addition of hydrogen to form a saturated
C = C
+H2 ¾¾®
CH – CH
- E(kcal)
where E is the heat of hydrogenation.
Lesser the heat of hydrogenation, lesser is the internal energy and more is stability of the system. Hyperconjugation decreases the heat of hydrogenation. For ethylene it is 32.8 kcal/mol and for propylene, 30.1 kcal/mol respectively.
- Dipole moment : Since hyperconjugation causes the development of charges, it also affects the dipole moment in the
The increase in dipole moment, when hydrogen of formaldehyde
(m = 2.27D)
is replaced by methyl group,
i.e., acetaldehyde (m = 2.72D) can be referred to hyperconjugation, which leads to development of charges.
H
|
H – C = O
(m =2.27 D)
H +
|
|
H – C – CH = O ¬¾® H – C
| |
H H
(m =2.72D)
–
== CH – O
- Orienting influence of alkyl group in
o, p -positions and of
- CCl3
group in m -position :
Ortho-para directing property of methyl group in toluene is partly due to + I
hyperconjugation.
effect and partly due to
- Reverse Hyperconjugation : The phenomenon of hyperconjugation is also observed in the system given below,
X
|
- C– C = C ; where
|
X = halogen
In such system the effect operates in the reverse direction. Hence the hyperconjugation in such system is known as reverse hyperconjugation.
|
|
Cl Cl
Cl Cl
|
Å | Å
Cl – C – CH = CH2 ¬¾® Cl – C
= CH – CH ¬¾® Cl
2
C = CH – C H ¬¾® Cl – C = CH – C H
|
2 2
| |
Cl Cl
|
Cl
The meta directing influence and dectivating effect of reaction can be explained by this effect.
CX 3
group for electrophilic aromatic substitution
|
X X X X
|| || ||
Å Å
Å
Inductomeric effect
Inductomeric effect is the temporary effect which enhance the inductive effect and it accounts only in the presence of an attacking reagent.
Example,
H
HO– H – C – Cl
H
H
¾¾® HO…………C………… Cl
H
¾¾–C¾l – ® HO – C – H
H
H H
In methyl chloride the –I effect of Cl group is further increased temporarily by approach of hydroxyl ion.
Electromeric effect
- The phenomenon of movement of electrons from one atom to another in multibonded atoms at the demand of attacking reagent is called electromeric It is denoted as E-effect and represented by a curved arrow ( ) showing the shifting of electron pair.
|
Å
¾¾® –
A B :
Reagent
(2) Important features of electromeric effect
- It is a temporary effect
- It is brought into play instantaneously at the demand of the attacking However as soon as the attacking reagent is removed, original electronic condition is restored.
Cd + d –
attacking
Å attacking
Cd + = Od –
|
= O ¾¾¾¾®
reagent
C O
reagent removed
- The electromeric effect is of common occurrence during addition of polar reagents on C = C , C = O C º N bonds
- The effect involves the complete transference of p
- In this effect the displaced electrons leave their orbitals and take a new
- In this there is complete charge separation and ions are
and
- There are two types of electromeric effects, e., + E
effect or – E
effect.
- When the transfer of electrons take place towards the attacking reagent, the effect is called + E
addition of acids to alkenes.
effect. The
C + H Å ¾¾®
C+ – C ;
|
H
CH3
CH = CH2
Propene
+ H + ® CH3
Å
- C H
- CH3
Since, – CH3
group is electron repelling, the electrons are transferred in the direction shown.
The attacking reagent is attached to that atom on which electrons have been transferred.
- When the transfer of electrons takes place away from the attacking reagent, the effect is called – E
Example, The addition of cyanide ion to carbonyl compounds.
effect.
C = O + CN ¾¾®
C – O
|
CN
The attacking reagent does not attached to that atom on which electrons have been transferred.
- Direction of the shift of electron pair : The direction of the shift of electron pair can be decided on the basis of following
- When the groups linked to a multiple bond are similar, the shift can occur to either For example, in ethylene the shift can occur to any one of the carbon atoms.
Å ..
H 2 C = CH 2 ¾¾® H 2 C– C H 2
.. Å
Both are similar
H 2 C = CH 2 ¾¾® H 2 C– C H 2
- When the dissimilar groups are linked on the two ends of the double bond, the shift is decided by the direction of inductive For example, in propylene the shift can be shown in the following ways,
Å ..
CH3 – CH = CH 2 ¾¾® CH3 – C H – C H 2
…..(a)
.. Å
CH3 – CH = CH 2 ¾¾® CH3 – C H – C H 2
…..(b)
Due to electron repelling nature of methyl group, the electronic shift occurs according to Eq. (a) way and not by Eq. (b) way.
In the case of carbonyl group, the shift is always towards oxygen, i.e., more electronegative atom.
Å ..
C = O ¾¾® C– O
Note:®In cases where inductive effect and electromeric effect simultaneously operate, usually electrometric effect predominates.
Breaking of covalent bond of the compound is known as bond fission. A bond can be broken by two ways,
(1) Homolytic bond fission or Homolysis
- In homolysis, the covalent bond is broken in such a way that each resulting species gets its own This leads to the formation of odd electron species known as free radical.
. .
A : B ¾¾® A + B
Free radical
- The factor which favours homolysis is zero or a small difference in electronegativity between A and B .
- Homolysis takes place in gaseous phase or in the presence of non polar solvents
UV light, heat (³ 500o C), electricity and free radical.
(CCl4 ,CS2 ) , peroxide,
- Mechanism of the reaction in which homolysis takes place is known as homolytic mechanism or free radical
(2) Heterolytic bond fission or heterolysis
- In heterolysis, the covalent bond is broken in such a way that one species (i.e., less electronegative) is deprived of its own electron, while the other species gains both the
A : B ¾¾®
A : +
carbanion
Å
B
carbocation
Thus formation of opposite charged species takes place. In case of organic compounds, if positive charge is present on the carbon then cation is termed as carbocation. If negative charge is present on the carbon then anion is termed as carbonion.
- The factor which favours heterolysis is a greater difference of electronegativity between A and B .
- Mechanism of the reaction in which heterolysis takes place is known as heterolytic mechanism or ionic
- The energy required for heterolysis is always greater than that for homolysis due to electrostatic force of attraction between
Short lived fragments called reaction intermediates result from homolytic and heterolytic bond fission. The important reaction intermediates are free radicals, carbocations, carbonions, carbenes, benzyne and nitrenes.
Free radicals
A free radical may be defined as an atom or group of atoms having an odd or unpired electron. These result on account of homolytic fission of a covalent bond and are denoted by putting a dot (.) against the symbol of atom or group of atoms.
.
Cl ;
Chlorine free radical
.
H ;
Hydrogen free radical
.
H 3 C ;
Methyl free radical
H
| .
H3 C – C ;
|
H
C6 H5
|.
C6 H5 – C
|
C H
Ethyl free radical
6 5
Triphenyl methyl
radical
The first stable organic free radical was triphenyl methyl radical and it was prepared by Gomberg.
(1) Characteristics of free radical.
- The formation of free radical is initiated by heat, light or
. . . .
(a) Cl : Cl ¾¾Ene¾r¾gy ® Cl+ Cl
sunlight
(b)
H3 C : H ¾¾102¾kc¾al ® H3 C+ H
. . CH3 CH3 . .
(c)
H3 C – CH 2 – H ¾¾97k¾c¾al ® H3 C – C H 2 + H
(primary)
(d)
CH3
CH – H ¾¾94 k¾c¾al ®
CH3
C H + H
(secondary)
CH3
CH3 . . . .
- CH3
CH3
C – H ¾¾91k¾c¾al ® CH3 C+ H
CH3
- CH 2 = CH – CH 2 – H ¾¾86k¾c¾al ® CH 2 = CH – C H 2 + H
(allyl)
(tertiary)
. . . .
– CH2 – H ¾¾88k¾c¾al ®
- C H 2 + H
(benzyl)
- CH3 – NH 2 ¾¾hea¾t / lig¾ht ® C H3 + N H 2
- Free radicals are generally electrically
- There are seven electrons in the out most orbit of carbon of carbon free
- Owing to the presence of an odd electron; a carbon radical is paramagnetic in Due to this reason free radicals are highly reactive.
- Free radicals are neutral
- Chemical reactions which takes place with the formation of free radical as an intermediate are known as free radical These reactions takes place in three steps,
(a) Initiation (b) Propagation and (c) Termination Each of these steps, in turn, may involve two or more steps.
- Initiation step : In this step, homolytic bond fission takes place in the presence of initiator, e., peroxide,
hv , heat etc. The process is always endothermic.
. .
Cl – Cl ¾¾hv¾or ® Cl + Cl
D
DH = +ve
- Propagation step : Propagation step is always two or more than two step process and all propagation steps should be exothermic, otherwise free radical reactions would not take place.
Propagation step I : In this step, formation of free radical as reaction intermediate takes place. For example,
. .
CH3 – H + Cl ¾¾® C H3 + HCl
DH =
negative
Propagation step II : Reaction intermediate reacts with reagent to give the product.
. .
C H3 + Cl – Cl ¾¾® CH3 – Cl + Cl
DH =
negative
- Termination step : In this step, free radical formed in the last propagation step (generally propagation step
- II) is destroyed by the addition of free radical or by the addition of some impurities like CHCl3or CCl4 .
. .
Cl + Cl ¾¾® Cl2
Reaction velocity of free radical reaction is very-very high.
Note:®Certain compounds, known as inhibitor, retar velocity of free radical reactions. Common inhibitors
are O2 , I2 , p-benzoquinone and diphenylamine.
- Relative stabilities of free radicals : The tertiary alkyl free radicals are most stable and methyl free radial is least stable, e., the free radical formed easily has greater stability.
R
|.
R – C >
|
R
Tertiary free radical
R
|.
R – C >
|
H
Secondary free radical
H
|.
R – C
|
H
Primary free radical
H
|.
- H – C
|
H
Methyl radical
Benzyl and allyl free radicals are resonance stabilized hence are more stable than alkyl free radicals.
.
– C H2 ¬¾®
.
= CH2 ¬¾®
Benzyl free radical
.
= CH2 ¬¾®
= CH2
CH2 = CH – C H2 ¬¾® C H2 – CH = CH2 (Allyl)
Relative stability of free radicals are : Benzyl > allyl > 3o > 2o >1o > methyl, vinyl
The stability of various free radicals can be compared from their bond dissociation energies (the energy required for the homolytic cleavage of the covalent bond in the molecule to form two radicals). In general, the smaller the amount of energy required for bond breaking, the more
stable is the radical.
- Structure of alkyl free radicals : The carbon atom of alkyl free radicals which is bonded to only three atoms or groups of atoms
is sp2 hybridized. Thus, free radicals have a planar structure with odd
electron situated in the unused p -orbital at right angles to the plane of hybrid orbitals.
However, in the substituted alkyl radicals the
‘ s‘
character of
these orbitals has been found to increase, thus, tending to the pyramidal shape.
. . . .
C H3 < C H2 F < C HF2 < C F3 .
So, CF3 is essentially pyramidal in shape.
- Stereochemistry of free radicals : To learn about the stereochemistry of free radical We choose the reaction, chlorination of 1-chloro-2-methyl butane. The reaction products are,
H
C Et
|
Me CH Cl
Cl
¾¾C¾l2 ® C
hv Me Et
Me Et
+ C CH2Cl
CH2Cl Cl
If we review the insight of the reaction, it is clear that the reaction involves racemization at the reaction centre.
The free radical should have the
sp2
hybridisation. Obviously a
Cl2 molecule could attack either the upper or
lower lobe of the p -orbital with equal chances, leading to racemic mixture.
Intermediate ¾¾C¾l2 ® d – form+ l – form
(50%) (50%)
(5) Reactions involving free radicals,
- Chlorination of alkanes (ii) Pyrolysis of alkanes (iii) Wurtz reaction
- Anti-markownikoff rule (v) Kolbe electrolytic synthesis (vi) Polymerisation initiated by free
Carbonium ions (carbocations)
Carbocation is defined as a group of atoms which contain positively charged carbon having only six electrons. It is obtained by heterolytic fission of a covalent bond involving carbon atom. It is denoted by putting a positive charge (+) against the symbol of group of atoms.
(1) Characteristics of carbocations
- The formation of carbocations can be done,
Å
- By heterolysis of halogen compounds : (CH3 )3 – C – Cl ¾¾®(CH3 )3 C+ Cl
HÅ Å
- By protonation of alkenes or alcohols : CH2 = CH2 ⇌ C H2 – CH3
R – O – H
HÅ Å
⇌ R – OH2
–H2O
⇌
R+ + H2O
- By decomposition of Diazo compounds : C6H5
- N2
– Cl ¾¾–¾Cl ®
Å
C6 H5 N 2
¾¾–N¾2 ® Å
- N2
|
- Carbocations are not electrically
- There are six electrons in the out most orbit of carbon of carbocation e., 2 electrons less than octet.
- A carbocation is diamagnetic in nature due to all paired electrons.
- Carbocations are charged electrophiles e., they react with nucleophilic reagents. The order of reactivity of carbocations is, Primary (1o) > Secondary (2o) > Tertiary (3o)
- Types of carbocations : Carbocations can be classified into the following types,
(i) Alkyl carbocations
- When positive charge is present on the alkyl carbon, carbocation is known as alkyl
- Alkyl carbocation is of four types
Å
CH3
Methyl carbocation
Å
R – CH2
Primary alkyl carbocations
Å
R – C H – R
Secondary alkyl carbocations
Å
R3 C
Tertiary alkyl carbocations
- Stability of alkyl carbocations can be explained by
Inductive effect and Hyperconjugation.
- According to these two effects the stability order is as follows :
Å
R – C– R
|
R
Å
R – CH – R
Å
R – CH2
Å
C H3
Stability in decreasing order
- If a -atom with respect to carbocationic carbon has one or more than one lone pair of electrons then lone pair of electrons strongly stabilises a carbocation due to the
Alkoxy and amino groups are important substituents for such type of carbocations.
CH3
. . Å
Å . . Å Å
N – CH 2
is more stable than R – C– R ;
CH3 – O– CH2 is more stable than R – C– R
CH3
| . . |
R R
- Vinyl carbocation : When positive charge is present on vinylic carbon then carbocation is known as
Å
vinyl carbocation, CH2 = CH
This carbocation is the least stable because positive charge is present on the electronegative carbon.
Å
- Allyl carbocation : (CH2 = CH – CH2)
- When positive charge is present on the allylic carbon of the allyl group, the carbocation is known as allyl
- Allyl carbocations are more stable than the alkyl carbocations due to the Allyl carbocations are stabilised by delocalisation (or resonance).
- Allyl carbocations are of the following types,
Å
CH2 = CH – CH2
Primary
Å
CH2 = CH – CH – R
Secondary
Å
CH2 = CH – C– R
|
R
Tertiary
- Stability of primary, secondary and tertiary allyl carbocations can be compared by, Inductive effect and Thus, tertiary is more stable than secondary which is more stable than primary allyl carbocation.
(iv) Phenyl methyl carbocations
- When positive charge is present on benzyl carbon, carbocation is known as phenyl methyl
- Phenyl methyl carbocations are of three types,
- Stability of phenyl methyl carbocations can be explained by
- Number of resonating structures in decreasing order
- Stability in decreasing order.
- Phenyl methyl carbocations are more stable than allyl carbocations due to the number of resonating
(v) Aromatic carbocations
- Cations in which positive charge is present on carbon of aromatic system is known as aromatic
- Aromatic carbocations are so stable that even their solid states are For example tropolium
carbocation as tropolium bromide is a yellow solid. It fact tropolium carbocation is about than triphenyl methyl carbocation .
1011
times more stable
- Cations obeying Huckel (4n+2) rule are stable because they are aromatic and there is complete delocalisation of positive
(vi) Cyclopropyl methyl carbocations
- These carbocations are very stable They are more stable than benzyl carbocations.
- Stability of cyclopropy methyl carbocations increases with every cyclopropyl Thus additional cyclopropyl group has commulative additive effect on the stability. Thus,
Å
> CH >
Å
C H2
Stability in decreasing order
- The special stability is a result of conjugation between the bent orbitals of the cyclopropyl ring and the vacant- p -orbital of the cationic
- Relative : Stability of different types of carbocations in decreasing order
Å
> CH > >
Å
Å Å Å Å
(C6 H5 )3 C > (C6 H5 )2 CH > C6 H5 – CH2 ³ CH2 = CH – CH2 ³
Å Å Å Å Å
R – C– R > R – C H – R
|
R
Note : ® More stable is a carbocation, the more easily it is formed.
- Structure of carbocation : The carbon atom in carbocation is
- R – C H2
sp2
- C H3
- CH2 = C H
hybridised. The three
sp2
hybrid orbitals form three s bonds with hydrogen or
other carbon atoms of alkyl groups. The unhybridised p -orbital of carbon remains
vacant. Since it involves of 120o .
sp2
hybridisation, its structure is planar with a bond angle
(5) Reactions involving carbocations
- Electrophilic addition reactions (ii)
SN 1 reactions (iii) Electrophilic substitution reactions
(iv) Molecular rearrangement reactions, e.g., Pinacole-Pinacolone rearrangement.
(6) Rearrangement in carbocations
- Rearrangement takes place in primary and secondary
p -carbocation
Rearrangement
ter-carbocation or sec. carbocation
Driving force for rearrangement is the stability factor (Less stable species wants to convert into more stable species).
- For rearrangement, carbocation should have at least three (a, b and g ).
- If b -carbon has hydrogen as well as alkyl group then rearrangement is due to the migration of hydrogen in the form of hydride ion from b to a -carbon. If b -carbon has only hydrogens then hydrogen migrates. If b – carbon has only alkyl groups then alkyl group migrates from b to a -carbon.
H
| Å
CH3
Å | Å Å
CH3
– C – C H2
|
1.2 H shift
CH3
– C – CH3
|
; CH3 – C
|
– C H2
- CH3 shift
CH3 –
C – CH2
|
– CH3
CH3
p-Carbocation
Å
CH3
ter -Carbocation
Å
CH3
CH3
CH3 – CH2 – CH2 1.2 H shift
CH3 – C H – CH3
Note : ® If the number of products of the reaction is more than the expected products then product formation takes place by formation of carbocation and there is rearrangement in carbocation.
CH3
|
CH3 OH
| |
CH3 – C
|
- CH2 – Cl ¾¾NaO¾H ® CH3 – C
|
- CH2OH + CH3 – C
|
- CH2 – CH3
CH3
CH3
Carbanions
CH3
Rearranged product
A carbanion may be defined as a species containing a carbon atom carrying a negative charge. These are generated by the heterolytic fission of covalent bond involving carbon atom in which the atom linked to carbon goes without the bonding electrons.
It is denoted by putting a negative charge (–) against the symbol of group of atoms.
(1) Characteristics of carbanions,
- The formation of carbanions can be done,
- By attack of base on hydrogen atom : Organic compounds which possess a labile or acidic hydrogen have the tendency to produce carbanions as in the case of reactive methylene compounds which lose proton in presence of sodium ethoxide (C2 H5ONa) .
COOC2 H5
COOC H
|
CH2
COOC2 H5
Malonic ester
- C2 H5 O ® CH
COOC2 H5
- C2 H5OH
- By decarboxylation of carboxylate ion :
R – CH2 – C
O
¾¾® R – CH2 + CO2
O
- By the formation of organometallic compound ; CH3
- Carbanions are not electrically
- Cl ¾¾Mg¾/ eth¾er ® CH3
MgCl ¾¾®
C H 3
- MgÅCl
- There are eight electrons in the outermost orbit of carbanionic carbon hence its octet is
- A carbanion is diamagnetic in nature due to all paired electrons.
- Carbanions are charged nucleophiles e., they react with electrophilic reagents. The order of reactivity of carbanions is, Tertiary (3o) > Secondary (2o) >Primary (1o) (Decreasing order)
- Stability of carbanions : The stability of carbanion may be explained by
- Electronegativity of carbanionic carbon
Stability µ Electronegativity of carbanionic carbon µ % s -character of carbanionic carbon
|
CH3 – C H2
sp3
CH = C H
|
sp2
CH º C
sp
% s -character in increasing order. Stability in inceasing oder.
- Inductive effect : Stability of carbanions depends on the +I or – I group as follows :
- Stability µ 1
- I power of the group
CH3
R ® CH2
R ® CH2 ¬ R
R ® C ® R
R
+ I power in increasing order. Stability in decreasing order.
- Stability of carbanions µ – I
For example :
power of the group.
I C H2 Br
C H2 Cl
C H2 F
C H2
– I power of halo group is in increasing order Stability is in increasing order
- Delocalisation or Resonance : Allyl and benzyl carbanions are stabilised by delocalisation of negative
CH2 = CH – CH2
2
C6 H5 – CH2
4
(C6 H5 )2 CH
7
(C6 H5 )3 C
10
Number of resonating structures is in increasing order Stability is in increasing order.
- Stabilisation by sulphur and phosphorous : Attachment of carbanionic carbon of a sulphur and phosphorus atom causes an increase in carbanion
The cause of stability is due to the delocalisation of negative charge of carbanion by vaccant d -orbital
pp – dp bonding) of phosphorus and sulphur.
- Stabilisation by >C=O, –NO2 and CN groups present on carbanionic carbon :These groups stabilise carbanion by resonance
|
|
O
|| | O
CH2 – C– R
Carbanion (I)
¬¾®
CH2 = C– R
Enolate ion (II)
CH2 – N
O
(I)
¬¾®
CH2 = N
O
(II)
Contribution of structure (II) will be more than (I) because in (II) negative charge is present on electronegative oxygen.
(vi) Stability of Aromatic carbanions
- Anions in which negative charge is present on carbon of aromatic system is known as aromatic
- Aromatic carbanions are most stable
- Anions obeying Huckel rule are stable because they are aromatic and there is complete delocalisation of negative
Cyclopentadienyl anion
(3) Relative stability of different types of carbanions in decreasing order
Aromatic carbanion > Benzyl carbanion > Allyl carbanion > CH º C >
é
ê
ù
|
ú
CH2 = C H >
Alkyl carbanion êC H3 > R – C H2 > C H > R – C– Rú
|
|
ê | ú
ë R úû
- Structure of carbanion : The negatively charged carbon atom in
carbanion is
sp3
hybridised. Therefore, it has a pyramidal structure. Three of the
four
sp3
hybridised orbitals form 3s
bonds with hydrogen or carbon atom of the
alkyl group. The fourth sp3 hybrid orbital contains the lone pair of electrons.
Note : ® Geometry of allyl and benzyl carbanion is almost planar and hybridisation is sp2 .
- Methyl anion is isostructural (pyramidal) and isoelectronic (eight valency electrons) with
- The carbanions having three different bulky groups are not optically active. It is due to pyramidal structure of carbanion which is not rigid and shows a rapid equilibrium between following two enantiomeric pyramidal
R R
|
R¢ C C ¢
R¢ R¢
(5) Reactions involving carbanions
- Condensation reactions of carbonyl compounds, e., Aldol condensation, Perkin reaction, Reformatsky reaction etc.
- Condensation reaction of ester; Claisen
- Witting
Carbenes
The simplest carbene is
. .
C H2
which known as methylene. Substituted carbenes are simply named as
derivative of carbenes. For example,
. .
C6 H5 – C H
Phenyl carbene
. .
R – C – R
Dialkyl carbene
. .
C Cl2
Dichloro carbene
(1) Characteristics of carbnes
- Carbenes can be formed,
- By the photochemical decomposition or pyrolysis of aliphatic diazo compounds or
CH2 N2
¾¾hn o¾r he¾at ® : CH2 + N2 ;
R – CHN2 ¾¾hn o¾r he¾at ®
RCH :
- N2
Diazo methane
(UV )
Carbene
Alkyl carbene
RCO – CHN2 ¾¾hn o¾r he¾at ® RCO – CH :+ N2 ; CH2 = C = O ¾¾®: CH2 + CO
Acyl carbene
Ketene
Carbene
- By the action of a base on suitable polyhalogen
CHCl3 + C2H5ONa ¾¾® Chloroform
: CCl2+ Dichloro carbene
C2H5OH + NaCl
CHCl3 + (CH3 )3 CO
Tert. butoxide ion
⇌ (CH3 )3 C – OH+ : CCl3 ¾¾® : CCl2 + Cl –
- Carbenes are related to carbanions through the a -elimination reaction.
CHX3
¾¾alc.¾KOH¾¾/ D ®
|
C X3
. .
CX2 + X
- Carbenes are neutral, divalent, highly reactive carbon They works as electrophiles.
(2) Types and stability of carbenes
Carbenes are of two types
- Singlet : When both the electrons go into one orbital and have opposite spin (antiparallel), e., the unshared electrons are paired in one orbital and has a bent strucutre.
The singlet state is actually found to have
H – C – H
bond angle 103o
(between 90o to 120o ) and a C – H
bond length of 1.12Å. It is generally considered as the less stable.
- Triplet : When the two electrons go into different orbitals and have same spin (parallel), e., the unshared electrons are not paired. Such carbene would have a permanent magnetic moment and would exist in three closely grouped energy state, if it were placed in a magnetic field. Such a state is called triplet state and is believed to be a linear molecule.
With
H – C – H
bond angle
180o
and a
C – H
bond length of 1.03Å, it might be considered as a free
diradical and is more stable.
(3) Reactions involving carbenes
- Addition to alkenes : Formation of cyclo alkane derivatives, g.,
(a)
H2C = CH2 + : CH2 ® H2C – CH2
R
(b)
C = C
R R
+ ¯ CH2 ®
R
C – C
Ethene
H3C
C = C
Carbene
H
CH2
Cyclo propane
H3C
+ ¯ CH2 ®
Carbene
C – C
H H
Cis – alkene
H
Carbene (singlet)
H H
CH2
(Cis -)
H
Trans- 2- butene
CH3
(singlet)
H
CH2
(Trans -)
CH3
- Conversely, the triplet carbenes add on alkenes in a non-stereo specific manner to form both (cis- and trans-)
R
C = C
H
Cis – alkene
R R
+ CH2 ®
|
|
Carbene (Triplet)
C – C CH2
(Cis -)
R R H
- C – C
H H R
CH2
(Trans -)
- In case of conjugated or cumulative dienes, the addition always occurs exclusively at 1,2-position.
H2C = C = CH2 + : CH2 ® H2 C – C = CH2
1,2- propadiene
CH2
H2C = CH – CH = CH2 + : CH2 ® H2 C – CH– CH = CH2
1,3 – butadiene
CH2
- Insertion reactions : Carbenes are also used in its insertion between the C – H
bond, e.g.,
| |
— C— H+ : CH2 ® — C— CH2 – H
(Next homologue)
| |
H H
| |
H — C — H + : CH2 ® H — C — CH2 – H
|
H
Methane
|
H
Ethane
Further it can be inserted in all the possible positions (pri-, sec-, tert-).
CH3CH2CH2 H + : CH2 ® CH3CH2CH2CH3 and CH3 CHCH3
Propane
n– butane
|
CH3
Iso- butane
- Ring expansion reactions : These involve the addition of a halogeno carbene across a double bond followed by
(a)
- : CCl2 Dichloro carbene
¾¾CHC¾l3 /¾C2H¾5O¾N¾a ®
C Cl ¾¾- H¾Cl ®
|
Cl
N
3-chloro pyidine
(b)
Benzene
- : CHCl
Chloro carbene
¾¾®
Å
H
C
Cl
Tropylium chloride
H
Cl–
(c)
N H
Indole
- : CHCl
¾¾®
C Cl ¾¾- H¾Cl ®
N
| H
Quinoline
- Carbylamine reaction : By heating a mixture of primary amine and chloroform with ethanolic potassium hydroxide to form isocyanide (carbylamine) is known as carbylamine
RNH 2 + CHCl3 + 3KOH ® RNC + 3KCl + 3H 2 O
Mechanism :
CHCl3
¾¾OH¾- ®
: CCl3
¾¾®
: CCl2 +
Cl–
(- H2O)
Dichloro carbene
- Reimer-Tiemann reaction : Phenol on heating with chloroform and aqueous alkali followed by acid hydrolysis to yield salicylaldehyde is known as Reimer-Tiemann
OH OH
- CHCl3 + 3KOH ¾¾®
CHO
- 3KCl + 2H2O
Comparision of Free radical, Carbocation, Carbanion and Carbene
Characteristic | Free radical | Carbocation | Carbanion | Carbene |
Nature | Neutral having odd electron
sp2
Planar Paramagnetic . . . Ph3 C > Ph2 CH > Ph CH 2 > . CH2 = CH – CH2 > 3o > 2o > . . 1o > CH2 > CH2 = CH |
Positive charge on C
sp2
Planar Diamagnetic + + Ph3 C > Ph2 CH > + + PhCH 2 > CH 2 = CH – CH 2 >
3o > 2o > 1o > CH3 |
Negative charge on C
sp3 (non- conjugated) sp2 (Conjugated) Pyramidal/Planar
Diamagnetic
Ph3 C > Ph2CH > PhCH2 > Allyl> o o o CH2 > 1 > 2 > 3 |
Neutral, divalent |
with 2 unshared | ||||
electrons | ||||
Hybridisation | (i) sp2 (singlet) | |||
(ii) sp (triplet) | ||||
Structure | (i) Planar (singlet) | |||
(ii) Linear (triplet) | ||||
Magnetism | (i) Diamagnetic | |||
(ii) Paramagnetic | ||||
Stability order | Triplet > singlet |
- 1, 2-Didehydrobenzene, is
C6 H4
Benzyne
and its derivatives are called benzyne or arynes and the simplest member
- It is neutral reaction intermediate derived from benzene ring by removing two substituents, of ortho positions, one in the form of electrophile and other in the from of nucleophile leaving behind two electrons to be destributed between two
Abnormal p bond
Two sp2-orbitals ouside the ring
- Benzye intermediate is aromatic in
- When halobenzene is heated with sodamide formation of benzyne takes place.
Cl
¾¾NaN¾H¾2 ®
- (i) It behaves as dienophile and gives Diels-Alder reaction with
(ii) It reacts with strong nucleophile like
H 2 ¾¾®
NH 2
®
NH2
. .
Nitrenes (R – N : )
- The nitrogen analogous of carbenes are called
- There is posibility of two spin states for nitrenes depending on whether the two non-bonding electrons (the normal nitrogen lone pair remains paired) have their spins paired or
. .
R – .N.
These two are lone pair of electrons
These two may be paired or unpaired
- In general nitrenes obey Hunds rule and are ground state triplet with two degenerate sp -orbitals containing a single electron
R – N
Sp-Triplet nitrene
- Nitrenes can be generated, in situ, by the following methods,
- By action of
Br2
in presence of a base on a 1o
amide (Hofmann-bromamide reaction),
O é O
|| ê ||
O
|| . .
R – C– NH2 ¾¾Br2 ¾/ Na¾O¾H ®êR – C– NH2
¾¾OH¾- ® R – C– N – Br
1o Amide
ê
ê
ë
O
|| . .
– H2O . .
¾¾¾® R – C– N ¾¾Rea¾rran¾gem¾e¾nt ®O = C = N – Rù ¾¾KO¾H ® R – NH2 + K2CO3
– Br – . .
Isocyanate
úû (Hydrolysis)
1o Amine
- By decomposition of azides in presence of heat or light.
. . + . . . .
R – N = N = N :–
Alkyl azide
¾¾D or ¾hν ® R – N : + N º N
Alkyl nitrene
. .
- Unsubstituted nitrene
(H – N 🙂 can be obtained by photolysis of (or by passing electric discharge
through)
NH3 , N2 H4
or N3 H .
Most of the attacking reagents carry either a positive or a negative charge. The positively charged reagents attack the regions of high electron density in the substrate molecule while the negatively charged reagents will attack the regions of low electron density in the substrate molecule. The fission of the substrate molecule to create centres of high or low electron density is influenced by attacking reagents. Most of the attacking reagents can be classified into two main groups.
(1) Electrophiles or electrophilic reagents. (2) Nucleophiles or nucleophilic reagents.
- Electrophiles : Electron deficient species or electron acceptor is It can be classified into two categories :
- Charged electrophiles (EÅ ), (ii) Neutral electrophiles (E)
- Charged electrophiles : Positively charged species in which central atom has incomplete octet is charged
Å O Å Å
H Å , X Å , RÅ , N , N = O, SO3 H
O . .
Note : ® All cations are charged electrophiles except cations of IA, IIA group elements,
- Neutral electrophiles : It can be classified into three categories,
Al +++
Å
and NH4
- Neutral covalent compound in which central atom has incomplete octet is neutral electrophile,
. . . . .
BeCl2 , BH3 , ZnCl2 , AlX3, FeX3 , CH3 , CH2 , CX2
- Neutral covalent compound in which central atom has complete or expended octet and central atom has unfilled –d-sub-shell is neutral electrophile,
SnCl4 , SiCl4 , PCl5 , SF6 , IF7
- Neutral covalent compound in which central atom is bonded only with two or more than two electronegative atoms is neutral
BeCl2 , BX3 , AlX3 , FeX 3 , SnCl4 , PCl3 ;
PCl5 ,
NF3 ,
..
C X 2 ,
CO2 , SO3 ,
CS2 ,
Note : ® Cl2, Br2 and
I 2 also behave as neutral electrophiles.
- Electrophiles are Lewis acids.
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