- Which is isoelectronic with carbon atom?
(A) Na+ (B) Al3+
(C) O2– (D) N+
- At ordinary temperature and pressure, among halogens, chlorine is a gas, bromine is a liquid and iodine is a solid. This is because
(A) The specific heat is in the order Cl2 > Br2 > I2
(B) Intermolecular forces among molecules of chlorine are in the weakest and those in iodine are the strongest.
(C) The order of density is Br2 > I2 > Cl2
(D) The order of stability is Cl2 > Br2 > I2
- Which property of halogens increase from F to I
(A) Electronegativity (B) First ionisation energy
(C) Bond length in the molecule (D) None
- Which of the following does not show inert pair effect
(A) Al (B) Sn
(C) Pb (D) Thallium
- Which of the following shows the highest lattice energy?
(A) RbF (B) CsF
(C) NaF (D) KF
- The species which does not show paramagnetism is
(A) O2 (B) O2+
(C) O22– (D) H2+
- The shape of a molecule which has three bond pairs and one lone pairs is
(A) Octahedral (B) Triangular planar
(C) Pyramidal (D) Tetrahedral
- Which of the following molecule is T-shaped?
(A) BeF2 (B) BCl3
(C) NH3 (D) ClF3
- The pair having similar geometry is
(A) BF3, NH3 (B) BF3, AlF3
(C) BeF2, H2O (D) BCl3, PCl3
- How many unpaired electrons are present in N2+
(A) 1 (B) 2
(C) 3 (D) 4
- PCl5 exist, but NCl5 does not exist because
(A) Nitrogen has no vacant 2-d orbital (B) NCl5 is unstable
(C) N-atom is much smaller than P (D) Nitrogen is highly inert
- The following compounds have been arranged in order of their increasing thermal stabilities identify the correct order
CaCO3(III) BeCO3 (IV)
(A) I < II < III < IV (B) IV < II < III < I
(C) IV < II < I < III (D) II < IV < III < I
- The conjugate base of OH– ion is
(A) H2O (B) O2–
(C) H3O+ (D) O–
- Which salts undergoes hydrolysis
(A) CH3COONa (B) KNO3
(C) NaCl (D)K2SO4
- The compound HCl behaves as …. in the reaction
HCl + HF ⎯→ H2+Cl + F–
(A) Strong acid (B) Strong base
(C) Weak acid (D) Weak base
- Which of the following is an acid anhydride?
(A) BaO (B) Na2O
(C) CO2 (D) CO
- The anhydride of H3PO4 is
(A) P2O5 (B) P2O3
(C) PO2 (D) None
- The conjugate base of hydrazoic acid is
(A) HN3– (B) N3–
(C) N3– (D) N2–
- Stainless steel contains iron and carbon along with
(A) Ni and Cr (B) Cr and Co
(C) Co and Mn (D) Mn and Ni
- A group of atoms can function as a ligand only when
(A) It is a small molecule (B) It has an unshared electron pair
(C) It is a negatively charged ion (D) It is a positively charged ion
- In the metal carbonyls of the general formula M(CO)x where M = metal, x = 4, the metal is bonded to
(A) C ≡ O triple bond (B) Carbon and oxygen
(C) Carbon (D) Oxygen
- Coordination number and oxidation state number of Cr in K3Cr(C2O4)3 are respectively
(A) 6 and +3 (B) 3 and 0
(C) 4 and +2 (D) 3 and +3
- The compound which does not show paramagnetism is
(A) [Cu(NH3)4]Cl2 (B) [Ag(NH3)2]Cl
(C) NO (D) NO2
- NH4SCN can be used to test
(A) Fe3+ only (B) Co2+, Cu2+
(C) Fe3+, Cu2+ (D) All
- Ag2S is soluble in NaCN due to formation of
(A) Na[Ag(CN)2] (B) Ag(CN)2
(C) Na2Ag(CN)3 (D) Na2[Ag(CN)2]
- There is foul smell in presence of moisture with
(A) AlCl3 (B) Al2(SO4)3
(C) FeS (D) FeSO4
- AgNO3 gives white ppt. with hypo changing to black after some time. Black ppt. is of
(A) Ag2S2O3 (B) Ag2SO4
(C) Ag2S4O6 (D) Ag2S
- Yellow coloured solution of FeCl3 changes to light green when
(A) SnCl2 is added (B) Zn is added
(C) H2S gas is passed (D) all true
- Which of the following oxides of nitrogen combines with Fe (II) ions to form a dark brown complex?
(A) N2O (B) NO
(C) NO2 (D) N2O5
- Of the following acids
I : hypo phosphorous acid II: hydroflouric acid
III: oxalic acid IV: glycine
(A) I, II are monobasic, III dibasic acid and IV amphoteric
(B) II monobasic, I, III dibasic acid, IV amphoteric
(C) I monobasic, II, III dibasic, IV amphoteric
(D) I, II, III dibasic, IV amphoteric
- In the following statements, select the correct statement:
(A) N(CH3)3 has pyramidal structure
(B) N(SiH3)3 shows planar arrangement
(C) both correct
(D) none is correct
- A solution of sodium in liquid ammonia is strongly reducing agent due to the presence of
(A) Na atoms (B) Sodium hydride
(C) sodium amide (D) solvated electron
- Nitrophenol, C6H4(OH) (NO2) can have:
(A) No isomer ( only a single compound is possible)
(B) Two isomers
(C) Three isomers
(D) Four isomers
- Geometrical isomerism is possible in:
(A) Butene-2 (B) Ethene
(C) Propane (D) Propene
- Which of the following compounds will exhibit cis-trans isomerism.
(A) 2-butene (B) 2-butyne
(B 2-butanol (D) Butanol
- Dichloro ethylene shows.
(A) Geometrical isomerism (B) Position isomerism
(C) Both (D) None
- The compound having molecular formula C4H10O can show
(A) Metamerism (B) Functional isomerism
(C) Positional isomerism (D) All
- A compound contains 2 dissimilar asymmetric carbon atoms. The number of optical
(A) 2 (B) 3
(C) 4 (D) 5
- The greater the s-character in an orbital the ———— is its energy
(A) Greater (B) Lower
(C) Both (D) None
40. The type of isomerism observed in urea molecule is
(A) Chain (B) Position
(C) Geometrical (D) Functional
- Number of possible isomers of glucose is
(A) 10 (B) 14
(C) 16 (D) 20
- Which of the following statement is correct?
(A) Allyl carbonium ion (CH2=CH–) is more stable than propyl carbonium ion
(B) Propyl carbonium ion is more stable than allyl carbonium ion
(C) Both are equally stable
- Which of the following would enable you to remove SO42– ions from a mixture of C2O42- and Cl– ions?
(A) NaOH (B) KOH
(C) Ba(OH)2 (D) BaSO4
- Which of the following sulphates is insoluble in water?
(A) CuSO4 (B) CdSO4
(C) PbSO4 (D) Bi(SO4)3
- A fire work gave bright crimson light. It probably contained a salt of
(A) Ca (B) Sr
(C) Ba (D) Mg
- Among the following compounds the one that is polar and has the central atoms with sp2 hybridisation is
(A) H2CO3 (B) SiF4
(C) BF3 (D) HClO2
- In the formation of N2+ from N2 the electron is removed from
(A) A σ orbital (B) A π-orbital
(C) A σ* M orbital (D) A π-M orbital
- CO2 has the same geometry as
(A) HgCl2 (B) NO2
(C) SnCl2 (D) C2H4
- Among the following species identify the isostructural pairs
NF3, NO3–, BF3 H3O+, HN3
(A) [NF3, NO3– and [BF3H3O+] (B) [NF3, HN3] and [NO3–, BF3]
(C) [NF3, H3O+] and [NO3–, BF3] (D) [NF3, H3O+] and [HN3, BF3]
- In which of the following alcohols C – O bond breaks (heterolytically) with greatest case:
- D 2. B
- C 4. A
- B 6. C
- C 8. D
- B 10. A
- A 12. B
- B 14. A
- D 16. C
- A 18. B
- C 20. B
- C 22. D
- B 24. D
- A 26. C
- D 28. D
- B 30. A
- C 32. D
- C 34. A
- A 36. C
- D 38. C
- A 40. D
- C 42. A
- C 44. C
- B 46. A
- A 48. A
49 C 50. C
HINTS & SOLUTIONS
- ClF3 has sp3d hybridisation with two lone pairs of electron on central Cl-atom.
- both have sp2 hybridisation of central atom.
- In N2 all electrons are paired. Thus N2+ has one unpaired electron.
- The excitation of 2s electron is not possible
- The stability of carbonates increases with increasing electropositive character of metal.
- Salt of strong acid and strong base does not undergo hydrolysis.
- HCl is accepting proton in HF medium and acts as weak base.
- P has +5 oxidation number in P2O5 and H3PO4
- N3H N3–
- o-,m- and p-isomers, i.e., position isomers
If either of the two doubly bonded carbon atoms has same group or atoms attached on it, it will not show geometrical isomerism.
- Due to the presence of asymmetric carbon atom.
- CH2 = CCl2 and CHCl = CHCl are position isomers; CHCl = CHCl also show geometrical isomerism.
- Alcohols show position isomerism; Ethers show metamerism; Alcohol and ethers shows functional isomerism.
- a = 2n; where n is no. of dissimilar asymmetric carbon atoms.
- Bond energy order
sp–sp > sp2-sp2 > sp3-sp3
- NH4CNO is functional isomer of urea.
- Glucose has four dissimilar asymmetric carbon atoms; a = 24.
- Allyl carbonium undergoes resonance stabilization.
- Carbon in H2CO3 has sp2 hybridisation and also polar. BF3 has sp3 hybridisation but non-polar. SiF4 has sp3 hybridisation. HClO2 has sp3 hybridisation.
- See the electronic configuration of N2
- HgCl2 is linear like CO2 because of sp2
- NF3and H3O+ have sp3 hybridisation; NO3– and BF3have sp2 hybridisation